4m^2=72m

Solution for 4m^2=72m equation:

4m^2=72m

We move all terms to the left:

4m^2-(72m)=0

a = 4; b = -72; c = 0;
Δ = b2-4ac
Δ = -722-4·4·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-72}{2*4}=\frac{0}{8}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+72}{2*4}=\frac{144}{8}
=18
$